29=2x^2+24x

Solution for 29=2x^2+24x equation:

29=2x^2+24x

We move all terms to the left:

29-(2x^2+24x)=0

We get rid of parentheses

-2x^2-24x+29=0

a = -2; b = -24; c = +29;
Δ = b2-4ac
Δ = -242-4·(-2)·29
Δ = 808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{808}=\sqrt{4*202}=\sqrt{4}*\sqrt{202}=2\sqrt{202}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{202}}{2*-2}=\frac{24-2\sqrt{202}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{202}}{2*-2}=\frac{24+2\sqrt{202}}{-4}
$